Optimal. Leaf size=107 \[ -\frac {6 \sqrt {1-x^2}}{5 x}-\frac {3 \sqrt {1-x^2}}{4 x^2}-\frac {3}{4} \tanh ^{-1}\left (\sqrt {1-x^2}\right )-\frac {\sqrt {1-x^2}}{5 x^5}-\frac {\sqrt {1-x^2}}{2 x^4}-\frac {3 \sqrt {1-x^2}}{5 x^3} \]
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Rubi [A] time = 0.10, antiderivative size = 107, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {1807, 835, 807, 266, 63, 206} \[ -\frac {6 \sqrt {1-x^2}}{5 x}-\frac {3 \sqrt {1-x^2}}{4 x^2}-\frac {3 \sqrt {1-x^2}}{5 x^3}-\frac {\sqrt {1-x^2}}{2 x^4}-\frac {\sqrt {1-x^2}}{5 x^5}-\frac {3}{4} \tanh ^{-1}\left (\sqrt {1-x^2}\right ) \]
Antiderivative was successfully verified.
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Rule 63
Rule 206
Rule 266
Rule 807
Rule 835
Rule 1807
Rubi steps
\begin {align*} \int \frac {(1+x)^2}{x^6 \sqrt {1-x^2}} \, dx &=-\frac {\sqrt {1-x^2}}{5 x^5}-\frac {1}{5} \int \frac {-10-9 x}{x^5 \sqrt {1-x^2}} \, dx\\ &=-\frac {\sqrt {1-x^2}}{5 x^5}-\frac {\sqrt {1-x^2}}{2 x^4}+\frac {1}{20} \int \frac {36+30 x}{x^4 \sqrt {1-x^2}} \, dx\\ &=-\frac {\sqrt {1-x^2}}{5 x^5}-\frac {\sqrt {1-x^2}}{2 x^4}-\frac {3 \sqrt {1-x^2}}{5 x^3}-\frac {1}{60} \int \frac {-90-72 x}{x^3 \sqrt {1-x^2}} \, dx\\ &=-\frac {\sqrt {1-x^2}}{5 x^5}-\frac {\sqrt {1-x^2}}{2 x^4}-\frac {3 \sqrt {1-x^2}}{5 x^3}-\frac {3 \sqrt {1-x^2}}{4 x^2}+\frac {1}{120} \int \frac {144+90 x}{x^2 \sqrt {1-x^2}} \, dx\\ &=-\frac {\sqrt {1-x^2}}{5 x^5}-\frac {\sqrt {1-x^2}}{2 x^4}-\frac {3 \sqrt {1-x^2}}{5 x^3}-\frac {3 \sqrt {1-x^2}}{4 x^2}-\frac {6 \sqrt {1-x^2}}{5 x}+\frac {3}{4} \int \frac {1}{x \sqrt {1-x^2}} \, dx\\ &=-\frac {\sqrt {1-x^2}}{5 x^5}-\frac {\sqrt {1-x^2}}{2 x^4}-\frac {3 \sqrt {1-x^2}}{5 x^3}-\frac {3 \sqrt {1-x^2}}{4 x^2}-\frac {6 \sqrt {1-x^2}}{5 x}+\frac {3}{8} \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-x} x} \, dx,x,x^2\right )\\ &=-\frac {\sqrt {1-x^2}}{5 x^5}-\frac {\sqrt {1-x^2}}{2 x^4}-\frac {3 \sqrt {1-x^2}}{5 x^3}-\frac {3 \sqrt {1-x^2}}{4 x^2}-\frac {6 \sqrt {1-x^2}}{5 x}-\frac {3}{4} \operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\sqrt {1-x^2}\right )\\ &=-\frac {\sqrt {1-x^2}}{5 x^5}-\frac {\sqrt {1-x^2}}{2 x^4}-\frac {3 \sqrt {1-x^2}}{5 x^3}-\frac {3 \sqrt {1-x^2}}{4 x^2}-\frac {6 \sqrt {1-x^2}}{5 x}-\frac {3}{4} \tanh ^{-1}\left (\sqrt {1-x^2}\right )\\ \end {align*}
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Mathematica [C] time = 0.02, size = 50, normalized size = 0.47 \[ -\frac {\sqrt {1-x^2} \left (10 x^5 \, _2F_1\left (\frac {1}{2},3;\frac {3}{2};1-x^2\right )+6 x^4+3 x^2+1\right )}{5 x^5} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.97, size = 58, normalized size = 0.54 \[ \frac {15 \, x^{5} \log \left (\frac {\sqrt {-x^{2} + 1} - 1}{x}\right ) - {\left (24 \, x^{4} + 15 \, x^{3} + 12 \, x^{2} + 10 \, x + 4\right )} \sqrt {-x^{2} + 1}}{20 \, x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.20, size = 199, normalized size = 1.86 \[ -\frac {x^{5} {\left (\frac {5 \, {\left (\sqrt {-x^{2} + 1} - 1\right )}}{x} - \frac {15 \, {\left (\sqrt {-x^{2} + 1} - 1\right )}^{2}}{x^{2}} + \frac {40 \, {\left (\sqrt {-x^{2} + 1} - 1\right )}^{3}}{x^{3}} - \frac {110 \, {\left (\sqrt {-x^{2} + 1} - 1\right )}^{4}}{x^{4}} - 1\right )}}{160 \, {\left (\sqrt {-x^{2} + 1} - 1\right )}^{5}} - \frac {11 \, {\left (\sqrt {-x^{2} + 1} - 1\right )}}{16 \, x} + \frac {{\left (\sqrt {-x^{2} + 1} - 1\right )}^{2}}{4 \, x^{2}} - \frac {3 \, {\left (\sqrt {-x^{2} + 1} - 1\right )}^{3}}{32 \, x^{3}} + \frac {{\left (\sqrt {-x^{2} + 1} - 1\right )}^{4}}{32 \, x^{4}} - \frac {{\left (\sqrt {-x^{2} + 1} - 1\right )}^{5}}{160 \, x^{5}} + \frac {3}{4} \, \log \left (-\frac {\sqrt {-x^{2} + 1} - 1}{{\left | x \right |}}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 84, normalized size = 0.79 \[ -\frac {3 \arctanh \left (\frac {1}{\sqrt {-x^{2}+1}}\right )}{4}-\frac {6 \sqrt {-x^{2}+1}}{5 x}-\frac {3 \sqrt {-x^{2}+1}}{4 x^{2}}-\frac {3 \sqrt {-x^{2}+1}}{5 x^{3}}-\frac {\sqrt {-x^{2}+1}}{2 x^{4}}-\frac {\sqrt {-x^{2}+1}}{5 x^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.97, size = 96, normalized size = 0.90 \[ -\frac {6 \, \sqrt {-x^{2} + 1}}{5 \, x} - \frac {3 \, \sqrt {-x^{2} + 1}}{4 \, x^{2}} - \frac {3 \, \sqrt {-x^{2} + 1}}{5 \, x^{3}} - \frac {\sqrt {-x^{2} + 1}}{2 \, x^{4}} - \frac {\sqrt {-x^{2} + 1}}{5 \, x^{5}} - \frac {3}{4} \, \log \left (\frac {2 \, \sqrt {-x^{2} + 1}}{{\left | x \right |}} + \frac {2}{{\left | x \right |}}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.04, size = 90, normalized size = 0.84 \[ \frac {3\,\ln \left (\sqrt {\frac {1}{x^2}-1}-\sqrt {\frac {1}{x^2}}\right )}{4}-\sqrt {1-x^2}\,\left (\frac {2}{3\,x}+\frac {1}{3\,x^3}\right )-\sqrt {1-x^2}\,\left (\frac {3}{4\,x^2}+\frac {1}{2\,x^4}\right )-\sqrt {1-x^2}\,\left (\frac {8}{15\,x}+\frac {4}{15\,x^3}+\frac {1}{5\,x^5}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [C] time = 12.69, size = 201, normalized size = 1.88 \[ \begin {cases} - \frac {\sqrt {1 - x^{2}}}{x} - \frac {\left (1 - x^{2}\right )^{\frac {3}{2}}}{3 x^{3}} & \text {for}\: x > -1 \wedge x < 1 \end {cases} + \begin {cases} - \frac {\sqrt {1 - x^{2}}}{x} - \frac {2 \left (1 - x^{2}\right )^{\frac {3}{2}}}{3 x^{3}} - \frac {\left (1 - x^{2}\right )^{\frac {5}{2}}}{5 x^{5}} & \text {for}\: x > -1 \wedge x < 1 \end {cases} + 2 \left (\begin {cases} - \frac {3 \operatorname {acosh}{\left (\frac {1}{x} \right )}}{8} + \frac {3}{8 x \sqrt {-1 + \frac {1}{x^{2}}}} - \frac {1}{8 x^{3} \sqrt {-1 + \frac {1}{x^{2}}}} - \frac {1}{4 x^{5} \sqrt {-1 + \frac {1}{x^{2}}}} & \text {for}\: \frac {1}{\left |{x^{2}}\right |} > 1 \\\frac {3 i \operatorname {asin}{\left (\frac {1}{x} \right )}}{8} - \frac {3 i}{8 x \sqrt {1 - \frac {1}{x^{2}}}} + \frac {i}{8 x^{3} \sqrt {1 - \frac {1}{x^{2}}}} + \frac {i}{4 x^{5} \sqrt {1 - \frac {1}{x^{2}}}} & \text {otherwise} \end {cases}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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